Question

The length l,breadth b and thickness t of a block of wood were measured with the help of a measuring scale. The result with permissible errors are: l = 15.12 + 0.10 cm, b=10.15 +0.1 cm,and t = 5.28 + 0.01 cm . The percentage error in volume up to proper significant figure is

• A. 0.28 %
• B. 1.81 %
• C. 0.48 %
• D. 0.68 %

Answer 1

The correct option is D 0.68 %

Given that,

Length $I=(15.12+0.10)cm$

Breadth $b=(10.15+0.1)cm$

Thickness $t=(5.28+0.01)cm$

We know that,

$V=Ibt$

$V=(15.12+0.10)(10.15+0.1)(5.28+0.01)cm$

$V=30.55+0.21$

Now, percentage error

$=\frac{V_{th}-V_p}{V_{th}}$

$=\frac{(30.55+0.21)-30.55}{30.55+0.21}$

$=\frac{0.21}{30.76}$

$=0.68$

Hence, this is the required solution