The length (l) of a cuboid is reduced by 7, height (h) becomes 3 times and width (w) is increased by 2'. Find its new volume.

$(l - 7) (3 h) w$

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$(l - 7) (w + 2) h$

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$(l - 7) (3 h) (w + 2)$

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$(l - 7) h w$

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Solution

The correct option is C
$(l - 7) (3 h) (w + 2)$

Volume of cuboid = length $\times$ height $\times$ width

Given, length (l) is reduced by 7.

Hence new length = $l - 7$

Given, height (h) becomes 3 times

Hence new height = $3 h$

Given, width (w) is increased by 2

Hence new width = $w + 2$

So, new volume = $(l - 7) (3 h) (w + 2)$

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The length (l) of a cuboid is reduced by 7, height (h) becomes 3 times and width (w) is increased by 2'. Find its new volume.

The correct option is C (l−7)(3h)(w+2) Volume of cuboid = length × height × width Given, length (l) is reduced by 7. Hence new length = l−7 Given, height (h) becomes 3 times Hence new height = 3h Given, width (w) is increased by 2 Hence new width = w+2 So, new volume = (l−7)(3h)(w+2)