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Question

The length of a ballistic pendulum is 1 m and mass of its block is 0.98 kg. A bullet of mass 20 g strikes the block along horizontal direction and gets embedded in the block. If block + bullet completes vertical circle of radius 1 m, the striking velocity of bullet is:

A
280 m/s
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B
350 m/s
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C
420 m/s
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D
490 m/s
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Solution

The correct option is C 350 m/s
Using conservation of momentum:
Initial momentum of bullet = Final momentum of bullet and pendulum
0.02×vi=(0.02+0.98)vf
So, vi=50×vf
Kinetic Energy after the collision=potential energy
12×1×v2f=1×g×2
vf=2g
Thus, vi=50×2g

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