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Continuity of a Function

The length of...

Question

The length of a brass scale is $1 m$ at $301 K$ . If the coefficient of linear expansion is $18 \times 10^{- 6} / K$ , what is its new length at $341 K$ ?

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Solution

For finding the expansion:
$L = L_{o} (1 + α T) (1) L_{o} = 1 m α = 18 \times 10^{- 6} / K (T - T_{o}) = △ T = 341 - 301 K △ T = 40 K$
Put values in equation $(1)$
$L = 1 (1 + 18 \times 10^{- 6} \times 40) L = 1.00072 m$

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