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Question

The length of a chord of a circle of 16.8 cm, radius is 9.1 cm. Find its distance from the centre.

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Solution


Length of the chord = 16.8 cm
Radius = 9.1 cm
Let the distance from the centre of the chord be d.
Perpendicular drawn from the centre of the circle to the chord bisects the chord.
So, AC = CB = 16.82=8.4 cm
In AOC,
Applying the Pythagoras theorem we have
OC2+AC2=AO2d2+8.42=9.12d2=82.81-70.56d2=12.25d=3.5 cm
Thus, the distance of chord from the centre is 3.5 cm.

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