The length of a chord which is at a distance of 5 cm from the centre a circle of radius 13 cm is
24 cm
Join OL
In the right triangle OAL
OA2 = OL2 + AL2
132 = 52 + AL2
AL2 = 144
AL = 12
Since the perpendicular from the centre to the chord bisects the chord, therefore
AB = 2AL = 24 cm