The length of a courtyard is $10 m$ and breadth $18$ . It is to be laid with bricks of length $22.5 c m$ and breadth $10 c m$ . Find the number of bricks required .

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Solution

Length of courtyard $= 10 m$
Breadth $= 18 m$
Area $= l \times b = 180 ㎡$
Length of each brick $= 22.5 ㎝$
Breadth $= 10 ㎝$
Area of each brick $= 22.5 \times 10 \times 10^{- 4} ㎡$
$= 22.5 \times 10^{- 4} ㎡$
No. of bricks required $= \frac{a r e a o f c o u r t y a r d}{a r e a o f e a c h b r i c k}$
$= \frac{180}{22.5 \times 10^{- 4}}$
$= \frac{1800000}{225}$
$= 8000$

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The length of a courtyard is 10m and breadth 18. It is to be laid with bricks of length 22.5cm and breadth 10cm. Find the number of bricks required .

Length of courtyard=10mBreadth=18mArea=l×b=180㎡Length of each brick=22.5㎝Breadth=10㎝Area of each brick=22.5×10×10−4㎡=22.5×10−4㎡No. of bricks required=areaofcourtyardareaofeachbrick=18022.5×10−4=1800000225=8000

The length of a courtyard is $10 m$ and breadth $18$ . It is to be laid with bricks of length $22.5 c m$ and breadth $10 c m$ . Find the number of bricks required .