Question

The length of a cuboidal room is $6$ metres , breadth is $4$ metres and height is $3$ metres.In this room how many cubic boxes of $1$ metre length can be arranged ?

Answer 1

Given :

The length of a cuboidal room is $6m$,

breadth of cuboidal room is $4m$,

height of cuboidal room is $3m$.

$\Rightarrow$ Volume of cuboid $=$ length $\times$ breadth $\times$ height.

$\therefore$ volume $=6$ $\times$$4$$\times$ $3=72$ $m^3$

Given length of the cubic box is $1m$.

$\Rightarrow$ volume of cube $=$$($length${)}^3$

$\therefore$ volume $=(1{)}^3=1m$

$\therefore$ We can arrange $=\frac{72}{1}=72$ cubes.