The length of a longest interval in which the function 3sinx−4sin3x is increasing is
A
π/3
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B
π/2
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C
3π/2
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D
π
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Solution
The correct option is Aπ/3 Since 3sinx−4sin3x=sin3x and sin3x increases when 3x takes values from −π/2 to π/2 or x takes values from −π/6 to π/6. Thus, the length of the longest interval in which 3sinx−4sin3x increases is π/6−(−π/6)=π/3. Ans: A