The length of a longest interval in which the function 3 $s i n x - 4 s i n^{3} x$ increases is

\frac{π}{6}

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\frac{π}{2}

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\frac{π}{3}

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π

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Solution

The correct option is C $\frac{π}{3}$
3 sin x - 4 $s i n^{3} x = s i n 3 x$ which increases from $x ϵ (- \frac{π}{6}, \frac{π}{6}),$ length is $\frac{π}{3}$

Suggest Corrections

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4 s i n^{3} x - 3 s i n x

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