The length of a metal wire is when the tension in it is T1 and when the tension in it is T2. The natural length of the wire:
A
l1+l22
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B
l1T2−T1l2T2−T1
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C
l1T2−l2T1T1+T2
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D
√l1l2
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Solution
The correct option is Bl1T2−T1l2T2−T1 For 1st case T1=k(l1−L)⋯(1) For 2nd case T2=k(l2−L)⋯(2) (1)÷(2) T1(l2−L)=T2(l1−L) T1l2−T1L=T2l1−T2L L=l1T2−T2l2T2−T1