Question

The length of a minute hand of a clock is 4 cm. Find the displacement and average velocity of the tip of the minute hand when it moves during a time interval from 4:15 pm to 4:45 pm.

Answer 1

The angle between the positions of 4.15 pm to 4.45 pm is ${180}^{\circ }$
$\therefore$ displacement $=2l$
$=2\times 4cm=8cm$
Time $=$ 30 min.
Average velocity $=\frac{displacement}{totaltimetaken}$
$=\frac{8cm}{30\times 60s}=\frac{1}{225}cm{s}^{-1}$