Question

The length of a minute hand of a clock is 4 cm. Find the displacement and average velocity of the tip of the minute hand when it moves during a time interval from 3: 15 pm to 3: 30 pm?

Answer 1

$l=4cm$
The angle between the positions of 3.15 pm to 3.30 is ${90}^{\circ }$
$\therefore$ displacement $=\sqrt{l^2+l^2}$
$=4\sqrt{2}cm$
Time $=$ 15 min
Average velocity $=\frac{displacement}{totaltimetaken}$
$=\frac{4\sqrt{2}cm}{15\times 60s}=\frac{\sqrt{2}}{225}cm{s}^{-1}$