The length of a needle floating on water is 2.5cm. The minimum force in addition to ties weight needed to lift the needle above the surface of water will be (surface tension of water is 0.072N/m)
A
3.6×10−3N
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B
10−2N
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C
9×10−4N
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D
6×10−4N
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Solution
The correct option is A3.6×10−3N One will have to overcome the downward surface tension force in addition to its weight. FT=2Tl∵There are two contact surfaces ⇒FT=2×0.072×2.5×10−2⇒FT=3.6×10−3N Note: Arrow in the diagram shows surface tension force.