Question

The length of a pendulum is doubled and the mass of its bob is halved. Its time period would

• A. become double
• B. become half
• C. become $\sqrt{2}$ times
• D. remain the same

Answer 1

The correct option is C become $\sqrt{2}$ times

$T=2\pi \sqrt{\frac{l}{g}}{T}^{{}^{\prime }}=2\pi \sqrt{\frac{2l}{g}}{T}^{{}^{\prime }}=\sqrt{2}T$