Question

The length of a rectangle exceeds its width by $8cm$ and the area of the rectangle is $240$ sq.cm. Find the dimensions of the rectangle.

Answer 1

Let the breadth of the given rectangle be $x$ cm.

Then, length $=(x+8)$ cm

Now area $=240{cm}^2$

$\Rightarrow length\times breadth=240\Rightarrow (x+8)x=240$

$\Rightarrow x^2+8x-240=0\Rightarrow x^2+20x-12x-240=0\Rightarrow (x+20)(x-12)=0$

$\Rightarrow x=12orx=-20$

But $x$ cannot be negative, So, $x=12$

Hence, length $=x+8=12+8=20cm$ and breadth $=12cm$