The length of a rectangle is 10 cm and breadth is 5 cm. If the breadth is decreased by 2 cm, the decrease in the area is equal to

$10 c m^{2}$

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$20 c m^{2}$

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$15 c m^{2}$

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$25 c m^{2}$

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Solution

The correct option is B
$20 c m^{2}$

Let ABCD be the rectangle with AB = 10cm and CB = 5cm

Let the breadth be decreased by 2 cm with AE = 2 cm

Area of original rectangle ABCD = $10 \times 5 c m^{2}$

Area of new rectangle EFCD = $10 \times (5 - 2)$

$= 10 \times 5 - 10 \times 2$

Hence, decrease in area $= 10 \times 2 = 20 c m^{2}$

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The length of a rectangle is 10 cm and breadth is 5 cm. If the breadth is decreased by 2 cm, the decrease in the area is equal to

The correct option is B 20 cm2 Let ABCD be the rectangle with AB = 10cm and CB = 5cm Let the breadth be decreased by 2 cm with AE = 2 cm Area of original rectangle ABCD = 10×5 cm2 Area of new rectangle EFCD = 10×(5−2) =10×5−10×2 Hence, decrease in area =10×2=20 cm2