Question

The length of a rectangle is $3$ cm more than its width and area is $54$ $c{m}^2$. Find the perimeter of the rectangle.

• A. $25$ cm
• B. $30$ cm
• C. $35$ cm
• D. $40$ cm

Answer 1

The correct option is B $30$ cm

Let the width be $x$
length $=x+3$
$x(x+3)=54$

$x^2+3x-54=0$
On factoring we get,
$(x+9)(x-6)=0$
$x=-9$ or $x=6$
So, length of the rectangle will be possible, if $x=9$
and width $=6$
Perimeter of the rectangle $=2\times (l+w)$
$=2(9+6)$
$=30$ cm