Question

The length of a rectangle is 6 cm and the breadth is 4 cm. If the length of another rectangle is 2 cm more than the first rectangle, how less is its breadth compared to the first rectangle, so that the new rectangle has the same area as the first one?

• A. 1 cm
• B. 2 cm
• C. 3 cm
• D. 4 cm

Answer 1

The correct option is A 1 cm

Given,
Length of the first rectangle = 6 cm
Breadth of the first rectangle = 4 cm
The area of a rectangle is given by, area = length x breadth.
So, the area of the first rectangle
= 6 cm x 4cm
= 24 <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> ${cm}^2$
Now, the length of the new rectangle is given, which is 2 cm more than the first rectangle = 6 cm + 2 cm = 8 cm
So, area of new rectangle
= 8 cm x breadth of new rectangle

Also, given that the new rectangle has the same area as the first one.
= 24 <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> ${cm}^2$ = 8 cm x breadth
= breadth = 3 cm

The breadth of the first rectangle is 4 cm and that of the new rectangle is 3 cm, so the breadth of the new rectangle is 1 cm less than the first rectangle.