Question

the length of a rectangle is 7 cm less than twice its breadth.if the length is decreased by 2 cm and breadth increased by 3 cm, the perimeter of the resulting rectangle is 66 cm.find the length and breadth of the original rectangle

Answer 1

Let breadth of rectangle $=b$

Length $=2b-7$

According to the question,

$2(2b-7-2+b+3)=66$

$2(3b-6)=66$

$3b-6=33$

$3b=39$

$b=13$

Therefore,

$l=19$

Hence, the length and breadth of the original rectangle are $19cm$ and $13cm$ respectively.