Question

The length of a rectangle is four times its width. Find the simplified expression for the perimeter and the area of the rectangle.
$(l=$ length of the rectangle, $w=$ width of the rectangle$)$

• A. $10wunits\&w^{2}squnits$
• B. $4wunits\&4w^{2}squnits$
• C. $10wunits\&4w^{2}squnits$
• D. $10wunits\&2w^{2}squnits$

Answer 1

The correct option is C $10wunits\&4w^{2}squnits$

Given:
$l=$ length of the rectangle
$w=$ width of the rectangle
According to the question, the length $l$ is $4$ times the width w of the rectangle.
So, $l=4w$
Perimeter of the rectangle $=2(l+w)=2(4w+w)=2\times 5w=10wunits$
The perimeter of the rectangle is $10wunits$.
Area of the rectangle $=l\times w=4w\times w=4w^{2}squnits$