Question

The length of a rectangle is greater than it breadth by 3 m. If its area be 10 sq. m., find the perimeter.

• A. $10m$
• B. $14m$
• C. $17m$
• D. $20m$

Answer 1

The correct option is B $14m$

Suppose, the breadth of the rectangle $=x$ m

Therefore, the length of the rectangle $=(x+3)$ m

So, area = $(x+3)x$ sq. m

Hence, by the condition of the problem,

$x^2+3x=10$

$x^2+3x-10=0$

$x^2+5x-2x-10=0$

$x(x+5)-2(x+5)=0$

$(x+5)(x-2)=0$

$x=2,-5$

Since, x cannot be negative. So, $x=2$.

Thus, $l=5m,b=2m$.

Hence, Perimeter = $2(l+b)=2(5+2)=14m$