The length of a rectangle is greater than the length of side of a square by 10 cm and its breadth is less by 6 cm than the side of the square. What is the perimeter of the rectangle if the areas of the square and the rectangle are equal?
68 cm
a2=l×b=(a+10)(a−6)⇒a2=a2+4a−60⇒a=15Perimeter=2[a+10+a−6]=2[2a+4]=68