Question

The length of a rectangle is three times its width (x). If the minimum perimeter of the rectangle is 240 ft, then what can be the possible values of its width?

Answer 1

Let the width of the rectangle be x.

According to the question, the length of the rectangle is three times the width.

$Length=3x$

$\text{Perimeter of the rectangle}=2(Length+Width)$

$=2(3x+x)$

$=2\left(4x\right)$

$=8x$

The minimum perimeter is 240 ft.

$\Rightarrow 8x\ge 240$

$\Rightarrow x\ge \frac{240}{8}$

$\Rightarrow x\ge 30$

The width of the rectangle should be greater than or equal to 30 ft.