The length of a rectangle is three times of its width- If the length of the diagonal is 8 -10 cm- then the perimeter of the rectangle is-A- 65 cmB- 15 -10 cmC- 16 -10 cm D- 24 -10 cmE- 64 cm

The correct option is E 64 cm Let breadth = `x' cm. Then, length = `3x' cm. x^2 + ( 3x)^2 = ( 8√(10))^2⇒ 10x^2 = 64 ⇒ x = 8 So, length = 24 m and breadth = 8 c ...

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Standard VIII

Mathematics

Rectangle

The length of...

Question

The length of a rectangle is three times of its width. If the length of the diagonal is $8 \sqrt{10}$ cm, then the perimeter of the rectangle is:

15√10 cm

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16√10 cm

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24√10 cm

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64 cm

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65 cm

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Solution

The correct option is D
64 cm

Let breadth = `x' cm. Then, length = `3x' cm. $x^{2} + {(3 x)}^{2} = {(8 \sqrt{10})}^{2} \Rightarrow 10 x^{2} = 64 \Rightarrow x = 8$ So, length = 24 m and breadth = 8 cm $∴$ Perimeter = [2 (24+8)] cm = 64 cm.

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Question 23

Length of a rectangle is three times its breadth. Perimeter of the rectangle is 40 cm. Find its length and width.

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The length of a rectangle is three times of its width. If the length of the diagonal is 8√10 cm, then the perimeter of the rectangle is:

The correct option is D 64 cm Let breadth = `x' cm. Then, length = `3x' cm. x2+(3x)2=(8√10)2⇒10x2=64⇒x=8 So, length = 24 m and breadth = 8 cm ∴ Perimeter = [2 (24+8)] cm = 64 cm.

The length of a rectangle is three times of its width. If the length of the diagonal is $8 \sqrt{10}$ cm, then the perimeter of the rectangle is:

The correct option is D
64 cm

Let breadth = `x' cm. Then, length = `3x' cm. $x^{2} + {(3 x)}^{2} = {(8 \sqrt{10})}^{2} \Rightarrow 10 x^{2} = 64 \Rightarrow x = 8$ So, length = 24 m and breadth = 8 cm $∴$ Perimeter = [2 (24+8)] cm = 64 cm.