The length of a rectangle is twice the width of it. If the perimeter of the rectangle is 42 m, find the area of the rectangle.

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Solution

The correct option is A

Let the breadth of rectangle be x
Length = 2x
Perimeter = 2 (length + breadth)
Perimeter, 2(x + 2x) = 42 m
$\Rightarrow$ 3x = 21 m
On solving, we get x = 7 m
Breadth = 7 m
Length = 14 m

Area = length $\times$ breadth = $98 m^{2}$

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The length of a rectangle is twice the width of it. If the perimeter of the rectangle is 42 m, find the area of the rectangle.

The correct option is A Let the breadth of rectangle be x Length = 2x Perimeter = 2 (length + breadth) Perimeter, 2(x + 2x) = 42 m ⇒ 3x = 21 m On solving, we get x = 7 m Breadth = 7 m Length = 14 m Area = length × breadth = 98 m2

The correct option is A

Let the breadth of rectangle be x
Length = 2x
Perimeter = 2 (length + breadth)
Perimeter, 2(x + 2x) = 42 m
$\Rightarrow$ 3x = 21 m
On solving, we get x = 7 m
Breadth = 7 m
Length = 14 m

Area = length $\times$ breadth = $98 m^{2}$