The length of a rectangle is twice the width of it. If perimeter of the rectangle is 42 m, find the area of the rectangle.

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Solution

The correct option is A

Let the breadth of rectangle be x.
Given, Length = 2x
$P e r i m e t e r = 2 (l e n g t h + b r e a d t h)$
$\Rightarrow 2 (x + 2 x) = 42 m$
$\Rightarrow 3 x = \frac{42}{2} m$

On solving, we get x = 7 m
Breadth = x= 7 m
Length = 2x = 14m

$A r e a = l e n g t h \times b r e a d t h$
$= 14 m \times 7 m$
$= 98 m^{2}$

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The length of a rectangle is twice the width of it. If perimeter of the rectangle is 42 m, find the area of the rectangle.

The correct option is A Let the breadth of rectangle be x. Given, Length = 2x Perimeter =2(length+breadth) ⇒ 2(x+2x)=42m ⇒3x=422m On solving, we get x = 7 m Breadth = x= 7 m Length = 2x = 14m Area =length×breadth =14 m×7 m =98 m2