The length of a rectangular field is $10$ meters more than its breadth. If its perimeter is $52$ meters, what are the length and the breadth of the field?

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Solution

Let the breadth be x, then length $= x + 10$
Perimeter $= 2 (l + b)$
$\Rightarrow 52 = 2 (x + x + 10)$
$\Rightarrow 26 = 2 x + 10$
$\Rightarrow 16 = 2 x$
So $x = 8$
$x + 10 = 18$
Length, Breadth $= 18, 8$ .

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The length of a rectangular field is 10 meters more than its breadth. If its perimeter is 52 meters, what are the length and the breadth of the field?

Let the breadth be x, then length =x+10Perimeter =2(l+b)⇒52=2(x+x+10)⇒26=2x+10⇒16=2xSo x=8x+10=18Length, Breadth =18,8.

The length of a rectangular field is $10$ meters more than its breadth. If its perimeter is $52$ meters, what are the length and the breadth of the field?

Let the breadth be x, then length $= x + 10$
Perimeter $= 2 (l + b)$
$\Rightarrow 52 = 2 (x + x + 10)$
$\Rightarrow 26 = 2 x + 10$
$\Rightarrow 16 = 2 x$
So $x = 8$
$x + 10 = 18$
Length, Breadth $= 18, 8$ .