The length of a rectangular field is 2 less than twice of the breadth. What is its area if the breadth is $b$ cm?

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Solution

Breadth = $b$ cm
Length = $2 b - 2$ cm
So, Area (in sq. cm) = length $\times$ breadth
$= (2 b - 2) \times b$
$= (2 b \times b) - (2 \times b)$
$= 2 b^{2} - 2 b$

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The length of a rectangular field is 2 less than twice of the breadth. What is its area if the breadth is b cm?

Breadth = b cm Length = 2b−2 cm So, Area (in sq. cm) = length × breadth =(2b−2)×b =(2b×b)−(2×b) =2b2−2b

The length of a rectangular field is 2 less than twice of the breadth. What is its area if the breadth is $b$ cm?

Breadth = $b$ cm
Length = $2 b - 2$ cm
So, Area (in sq. cm) = length $\times$ breadth
$= (2 b - 2) \times b$
$= (2 b \times b) - (2 \times b)$
$= 2 b^{2} - 2 b$