Question

The length of a rectangular field is twice its breadth and the perimeter of the field is $60m$. What are its dimensions ?

Answer 1

Let the breadth $\left(b\right)$ of the rectangular field be $x$

$\therefore \text{length}\left(l\right)=2x$

As we know that, perimeter of rectangle $\left(P\right)$ is given as-

$P=2(l+b)$

$\Rightarrow P=2(2x+x)$

$\Rightarrow P=2\left(3x\right)$

$\Rightarrow P=6x$

Given that perimeter $\left(P\right)$ of the rectangular field is $60m$

$\therefore 6x=60$

$\Rightarrow x=\frac{60}{6}=10m$

Therefore,

Breadt of the field $=10m$

Length of the field $=2\times 10=20m$