The length of a rectangular field is two more than thrice of the breadth. What is its area if the breadth is $x$ ?

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Solution

Breadth = $x$
Length = $3 x + 2$ $[1 m a r k]$
So, Area = length $\times$ breadth
$= (3 x + 2) \times x$
$= (3 x \times x) + (2 \times x)$
$= 3 x^{2} + 2 x$ $[1 m a r k]$

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The length of a rectangular field is two more than thrice of the breadth. What is its area if the breadth is x?

Breadth = x Length = 3x+2 [1 mark] So, Area = length × breadth =(3x+2)×x =(3x×x)+(2×x) =3x2+2x [1 mark]

The length of a rectangular field is two more than thrice of the breadth. What is its area if the breadth is $x$ ?

Breadth = $x$
Length = $3 x + 2$ $[1 m a r k]$
So, Area = length $\times$ breadth
$= (3 x + 2) \times x$
$= (3 x \times x) + (2 \times x)$
$= 3 x^{2} + 2 x$ $[1 m a r k]$