The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs.26.50 per metre is Rs. 5300, what is the length of the plot in metres?

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Solution

The correct option is D
60

Let breadth = `x' metres. Then, length = `(x + 20)' metres

Perimeter = $(\frac{5300}{26.50})$ m = 200 m.

$∴$ 2 [(x+20) + x] = 200 $\Leftrightarrow$ 2x = 80 $\Leftrightarrow$ x = 40.

Hence, length = x + 20 = 60 m

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The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs.26.50 per metre is Rs. 5300, what is the length of the plot in metres?

The correct option is D 60 Let breadth = `x' metres. Then, length = `(x + 20)' metres Perimeter = (530026.50)m = 200 m. ∴2 [(x+20) + x] = 200 ⇔ 2x = 80 ⇔ x = 40. Hence, length = x + 20 = 60 m

The correct option is D
60

Let breadth = `x' metres. Then, length = `(x + 20)' metres

Perimeter = $(\frac{5300}{26.50})$ m = 200 m.

$∴$ 2 [(x+20) + x] = 200 $\Leftrightarrow$ 2x = 80 $\Leftrightarrow$ x = 40.

Hence, length = x + 20 = 60 m