The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

40

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50

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120

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Data inadequate

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None of these

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Solution

The correct option is B $50$
Let length $= l$ breadth $= b$
$l = b + 20$
Perimeter of plot $= 2 (l + b)$
$= 2 (2 b + 20)$
$= 4 b + 80$
Now,
$26.50 \times (45 + 80) = 5300$
$\frac{26.5}{10} \times 4 b + \frac{265}{10} \times 80 = 5300$
$106 b = 3180$
$b = 30$
$\Rightarrow l e n g t h = 50 m .$

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The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

The correct option is B 50Let length=l breadth=bl=b+20Perimeter of plot=2(l+b)=2(2b+20)=4b+80Now,26.50×(45+80)=530026.510×4b+26510×80=5300106b=3180b=30⇒length=50m.

The correct option is B $50$
Let length $= l$ breadth $= b$
$l = b + 20$
Perimeter of plot $= 2 (l + b)$
$= 2 (2 b + 20)$
$= 4 b + 80$
Now,
$26.50 \times (45 + 80) = 5300$
$\frac{26.5}{10} \times 4 b + \frac{265}{10} \times 80 = 5300$
$106 b = 3180$
$b = 30$
$\Rightarrow l e n g t h = 50 m .$