The length of a rectangular room is 6 m longer than its width. If each dimensions is increased by 2 m , the area of the floor of the room increases by 64 sq.m. find the original dimensions of the room?

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Solution

Let width be x
then length = x+6

area=x(x+6)

now length and width are increased by 2
new width=x+2
new length=x+2+6=x+8
new area=(x+2)(x+8)

(x+2)(x+8)-x(x+6)=64
x∧2+8x+2x+16-x∧2-6x=64
4x+16=64
4x=64-16
4x=48
x=12
width=12m
length=12+6=18m

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The length of a rectangular room is 6 m longer than its width. If each dimensions is increased by 2 m , the area of the floor of the room increases by 64 sq.m. find the original dimensions of the room?

Let width be x then length = x+6 area=x(x+6) now length and width are increased by 2 new width=x+2 new length=x+2+6=x+8 new area=(x+2)(x+8) (x+2)(x+8)-x(x+6)=64 x∧2+8x+2x+16-x∧2-6x=64 4x+16=64 4x=64-16 4x=48 x=12 width=12m length=12+6=18m

Let width be x
then length = x+6

area=x(x+6)

now length and width are increased by 2
new width=x+2
new length=x+2+6=x+8
new area=(x+2)(x+8)

(x+2)(x+8)-x(x+6)=64
x∧2+8x+2x+16-x∧2-6x=64
4x+16=64
4x=64-16
4x=48
x=12
width=12m
length=12+6=18m