The length of a rectangular wooden board is 24 cm. If the area of the board is 192 $c m^{2}$ , find its perimeter.

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Solution

Let the length and breadth of the board be $l$ and $b$ respectively.

Given: Length = 24 cm
and area of the board = 192 cm $^{2}$ ...(1 Mark)

Area $= l \times b = 24 \times b = 192$

$\Rightarrow 24 b = 192$

$\Rightarrow b = 8 c m$ ...(1 Mark)

Perimeter $= 2 (l + b) = 2 (24 + 8)$
$= 2 \times 32 = 64 c m$ ...(1 Mark)

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The length of a rectangular wooden board is 24 cm. If the area of the board is 192 cm2, find its perimeter.

Let the length and breadth of the board be l and b respectively. Given: Length = 24 cm and area of the board = 192 cm2 ...(1 Mark) Area =l×b=24×b=192 ⇒24b=192 ⇒b=8 cm ...(1 Mark) Perimeter =2(l+b)=2(24+8) =2×32=64 cm ...(1 Mark)

The length of a rectangular wooden board is 24 cm. If the area of the board is 192 $c m^{2}$ , find its perimeter.