The length of a road roller is $2.1$ m and its diameter is $1.4$ m. For levelling a ground $500$ rotations of the road roller were required. How much area of ground was levelled by the road roller? Find the cost of levelling at the rate of Rs $7$ per sq.m

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Solution

$l = 2.1 m, d = 1.4 m ⟹ r = 0.7 m$
$n = 500$
Area covered $= 2 n π \times r \times l = 2 \times 500 \times 0.7 \times 2.1 π = 4620 m^{2}$
Cost of travelling $= 4620 \times 7 = R s .32, 340$

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The length of a road roller is 2.1m and its diameter is 1.4m. For levelling a ground 500 rotations of the road roller were required. How much area of ground was levelled by the road roller? Find the cost of levelling at the rate of Rs7 per sq.m

l=2.1m,d=1.4m⟹r=0.7mn=500Area covered=2nπ×r×l=2×500×0.7×2.1π=4620m2Cost of travelling =4620×7=Rs.32,340

The length of a road roller is $2.1$ m and its diameter is $1.4$ m. For levelling a ground $500$ rotations of the road roller were required. How much area of ground was levelled by the road roller? Find the cost of levelling at the rate of Rs $7$ per sq.m

$l = 2.1 m, d = 1.4 m ⟹ r = 0.7 m$
$n = 500$
Area covered $= 2 n π \times r \times l = 2 \times 500 \times 0.7 \times 2.1 π = 4620 m^{2}$
Cost of travelling $= 4620 \times 7 = R s .32, 340$