The length of a room is $10$ $m$ , breadth is $8$ $m$ and height is $2$ $m$ . Find the cost of painting the walls of the room at the rate of $R s . 100$ per $s q . m$ .

R s .24, 000

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R s .7, 200

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R s .24, 500

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R s .10, 200

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Solution

The correct option is B $R s .7, 200$
Given,
Length $= 10 m$
Breadth $= 8 m$
Height $= 2 m$

Lateral surface area $= 2 (l + b) h$
$= 2 (10 + 8) \times 2 s q . m$
$= 2 \times 18 \times 2 s q . m$
$= 72 s q . m$

Cost of painting $1 s q . m = R s .100$
Cost of painting $72 s q . m = R s .72 \times 100$
$= R s .7200$

Hence, the total cost of painting the walls is $R s .7200$ .

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