The length of a second pendulum at the surface of earth is 1m. The length of second pendulum at the surface of moon, where g is 16th that of earth's surface.
A
16m
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B
6m
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C
136m
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D
36m
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Solution
The correct option is A16m We know that the time period of a second pendulum is 2s .
At earth ,
T=2π√le/ge
2=2π√le/ge
or ge=π2le ...............................eq1
At moon ,
T=2π√lm/gm
or 2=2π√lm/(ge/6) , given gm=ge/6
or 2=2π√6lm/π2le , putting the value of gm from eq1