Question

The length of a side of a square field is $4m$ . What will be the altitude of the rhombus, if the area of the rhombus is equal to the square filed and one of its diagonal is $2m$?

• A. $\sqrt{65}$
• B. $8$
• C. $16$
• D. $\frac{16}{\sqrt{65}}$

Answer 1

Answer: (C)

$16$

Length of a side of square is $4m$ so

Assume that rhombus diagonal is $a$ and $b$.

given that one of diagonal is $2m$ so assume $a=2$

Then area of rhombus is $=\frac{1}{2}\times a\times b$

$=\frac{1}{2}\times 2\times b$

$=b{m}^2$

given area of rhombus = area of square

$b{m}^2=4m\times 4m$

$b{m}^2=16m^2$

$b=16$ Ans