Question

The length of a simple pendulum is $39.2{/\pi }^{2}m$. If $g=9.8m/{sec}^2$, the value of time period is :

• A. 4 s
• B. 8 s
• C. 2 s
• D. 3 s

Answer 1

Answer: (A)

4 s

Given,

$l=\frac{39.2}{{\pi }^2}m$

$g=9.8m/s^2$

The time period of simple pendulum,

$T=2\pi \sqrt{\frac{l}{g}}$

$T=2\pi \sqrt{\frac{39.2}{9.8{\pi }^2}}$

$T=2\times 2$

$T=4sec$

The correct option is A.