The length of a simple pendulum is 39-2-2 m- If g -9-8 m - s 2- the time period of pendulum is A- 2 sB- 8 sC- 4 sD- 3 s

Name: NEET - 11 - Physics - SHM & Oscillation - Session 04 - D02
Uploaded: 2022-07-04T10:36:42+05:30
Description: The correct option is C 4 s nbsp;Given, Length of simple pendulum (l)=39.2π^2 m acceleration due to gravity (g)=9.8 m/s^2 Time period (T)=2π√(lg) =2π√(39.29. ...

The correct option is C 4 s nbsp;Given, Length of simple pendulum (l)=39.2π^2 m acceleration due to gravity (g)=9.8 m/s^2 Time period (T)=2π√(lg) =2π√(39.29. ...

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Standard XII

Physics

Intro to Simple Pendulum

The length of...

Question

The length of a simple pendulum is $\frac{39.2}{π^{2}} m$ . If $g = 9.8 {m/s}^{2}$ , the time period of pendulum is

2 s

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8 s

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4 s

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3 s

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Solution

The correct option is C $4 s$
Given,
Length of simple pendulum $(l) = \frac{39.2}{π^{2}} m$
acceleration due to gravity $(g) = 9.8 {m/s}^{2}$
Time period $(T) = 2 π \sqrt{\frac{l}{g}}$
$= 2 π \sqrt{\frac{39.2}{9.8 \times π^{2}}}$
$= 4 s$

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Intro to Simple Pendulum

Standard XII Physics

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The length of a simple pendulum is 39.2π2 m. If g=9.8 m/s2, the time period of pendulum is

The correct option is C 4 s Given, Length of simple pendulum (l)=39.2π2 m acceleration due to gravity (g)=9.8 m/s2 Time period (T)=2π√lg =2π√39.29.8×π2 =4 s

The length of a simple pendulum is $\frac{39.2}{π^{2}} m$ . If $g = 9.8 {m/s}^{2}$ , the time period of pendulum is

The correct option is C $4 s$
Given,
Length of simple pendulum $(l) = \frac{39.2}{π^{2}} m$
acceleration due to gravity $(g) = 9.8 {m/s}^{2}$
Time period $(T) = 2 π \sqrt{\frac{l}{g}}$
$= 2 π \sqrt{\frac{39.2}{9.8 \times π^{2}}}$
$= 4 s$