The length of a trapezium shaped feild PQRS is 120 m. If QR=48 cm, RS= 17cm and PS=40, find the area of this field. Side PQ is perpendicular to the parallel sides PS and QR.

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Solution

The above solution is correct.
The total length is given in meters, then all the other sides also have to be in meter. Other wise it doesnt make any sense.
Hope you understand that.
and also, its the length of sides of a field. Ther is no way that is in cm. It has to be in meter.

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PQRS is a trapezium having PS and QR as parallel sides. A is any point on PQ and B is a point on SR such that AB || QR. If area of $△ P B Q$ is 17 cm^2, Find the ara of $△ A S R .$

Q. Suppose

E

F

are the midpoints respectively of the oblique sides

P S

Q R

of the trapezium

P Q R S

. Prove that

E F

is parallel to

S R

and

E F = \frac{P Q + R S}{2}

Q. PQRS is a trapezium having PS and QR as parallel sides. A is any point on PQ and B is a point on SR such that AB || QR. If area of ΔPBQ is 17cm², find the area of ΔASR.

Q. PQRS is a trapezium such that PQ || RS and PQ = 10 cm, QR = 5 cm, RS = 8 cm and PS = 5 cm, then area of PQRS is

Q. Let

□ P Q R S

be a quadrilateral. If

M

and

N

are midpoints of the sides

P Q

and

R S

respectively then

¯ ¯¯¯¯¯¯ ¯ P S + ¯ ¯¯¯¯¯¯¯ ¯ Q R =

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The length of a trapezium shaped feild PQRS is 120 m. If QR=48 cm, RS= 17cm and PS=40, find the area of this field. Side PQ is perpendicular to the parallel sides PS and QR.

The above solution is correct. The total length is given in meters, then all the other sides also have to be in meter. Other wise it doesnt make any sense. Hope you understand that. and also, its the length of sides of a field. Ther is no way that is in cm. It has to be in meter.

The above solution is correct.
The total length is given in meters, then all the other sides also have to be in meter. Other wise it doesnt make any sense.
Hope you understand that.
and also, its the length of sides of a field. Ther is no way that is in cm. It has to be in meter.