Question

The length of a vertical pole at the surface of a lake of water $(\mu =\frac{4}{3})$ is 24 $cm.$ Then to an under-water fish just below the water surface the tip of the pole
appears to be

• A. 18 cm above the surface
• B. 24 cm above the surface
• C. 32 cm above the surface
• D. 36 cm above the surface

Answer 1

The correct option is C 32 cm above the surface

Given now,

Actual height $=24$cm

Apparent height=/

Apparent height>actual height and

$\mu =4/3$

$\begin{array}{c}u=\frac{apparentheight}{actualheight}\\ \therefore \frac{4}{3}=\frac{apparentheight}{24}\\ Apparentheight=32cm\end{array}$

Hence, Option $C$ is correct.