You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Longitudinal Stress

The length of...

Question

The length of a wire is $4 m$ . Its length is increased by $2 m m$ when a force acts on it. The strain is:

0.5 x 10

^{- 3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 x 10

^{- 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 x 10

^{- 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.05

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 0.5 x 10 $^{- 3}$
$L^{'} = 4.002 m$
$S t r a i n = \frac{0.002}{4}$ $= 5 \times 10^{- 4}$ (using standard result)

Suggest Corrections

Similar questions

When a force is applied on a wire of uniform cross-sectional area $3 \times 10^{- 6} m^{2}$ and length $4 m$ , the increase in length is $1 m m$ . Energy stored in it will be

$(Y = 2 \times 10^{11} N m^{- 2})$

Q. Q. When a load of 10 kg is suspended on a metallic wire its length increases by 2 mm the force constant of the wire is
(1) 3×10⁴ N/m
(2) 2.5×10³ N/m
(3) 5×10⁴ N/m
(4) 7.5×10³ N/m

Q. A particular force

F

applied on a wire increases its length by

2 \times 10^{- 3} m

. If we were to increase the wire's length by

4 \times 10^{- 3} m

, then the applied force should be

Q. When a force is applied on a wire of uniform cross-sectional area

3 \times 10^{- 6} m^{2}

and length

4 m

, the increase in length is

1 m m

. Energy stored in it will be (

Y = 2 \times 10^{11} N / m^{2}

Q. When a wire of length 10m is subjected to a force of

100 N

along its length , the lateral strain produced is

0.01

10

^{- 3}

. The Poisson's ratio was found to be

0.4

. If the area of cross-section of wire is

0.025 m

^{2}

, its Young's modulus is :

Join BYJU'S Learning Program

The length of a wire is 4m. Its length is increased by 2mm when a force acts on it. The strain is:

The correct option is A 0.5 x 10−3L′=4.002mStrain=0.0024=5×10−4 (using standard result)

The length of a wire is $4 m$ . Its length is increased by $2 m m$ when a force acts on it. The strain is:

The correct option is A 0.5 x 10 $^{- 3}$
$L^{'} = 4.002 m$
$S t r a i n = \frac{0.002}{4}$ $= 5 \times 10^{- 4}$ (using standard result)