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Question

The length of a wire of a potentiometer is 100 cm and the end of its standard cell is E volt . It is employed to measure the emf of a battery whose internal resistance is 0.5 ohm. If the balance point is obtained at L=30cm from the positive end , the emf of battery is 1. 30E/100.5 2. 30E/100-0.5 30(E-0.5i)/100, where I is the current in the potentiometer wire 4. 30E/100

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Solution

99996148086-0-0

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