The length of an arc of a sector of a circle of radius r units and of centre angle $θ$ is $\frac{θ}{360^{\circ}} \times π r^{2}$ .

True

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False

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Neither

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Either

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Solution

The correct option is B False
$L e n g t h o f a n a r c o f a c i r c l e = \frac{θ}{360} \times 2 π r$

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Similar questions

θ

θ

\frac{θ}{360} \times m π r

m

r units

θ

The length of an arc of a sector of angle $θ^{\circ}$ of a circle with radius R is

(a) $\frac{2 π R θ}{180}$

(b) $\frac{2 π R θ}{360}$

(d) $\frac{π R^{2} θ}{360}$

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