The length of an elastic string is a metre when the longitudinal tension is 4 N and b metre when the longitudinal tension is 5 N. The length of the string in metre when the longitudinal tension is 9 N is
A
a−b
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B
5b−4a
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C
2b−14a
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D
4a−3b
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Solution
The correct option is B5b−4a Let the original length of elastic string is L and its force constant is k. When longitudinal tension 4N is applied on it L+5K=a⋯ (i)
and when longitudinal tension 5N is applied on it L+5K=b⋯ (ii)
By solving (i) and (ii) we get k=1b−aandL=5a−4b
Now when longitudinal tension 9N is applied on elastic string then its length =L+9K=5a−4b+9(b−a)=5b−4a