The length of canvas 2 m wide needed to make a conical tent of radius of base 4 m and height 3 m is (use $π = 3.14$ )

18.48 m

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14.13 m

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18.84 m

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9.42 m

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Solution

The correct option is C 18.84 m
$l = \sqrt{4^{2} + 3^{2}} m = 5 m$
CSA = $π r l$ = 3.14 x 4 x 3 $c m^{2}$ = 37.68 $c m^{2}$
Now l x 2 = 37.68 $\Rightarrow$ l = 18.84 m

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The length of canvas 2 m wide needed to make a conical tent of radius of base 4 m and height 3 m is (use π=3.14)

The correct option is C 18.84 ml=√42+32m=5mCSA = πrl = 3.14 x 4 x 3 cm2 = 37.68 cm2Now l x 2 = 37.68 ⇒ l = 18.84 m

The length of canvas 2 m wide needed to make a conical tent of radius of base 4 m and height 3 m is (use $π = 3.14$ )

The correct option is C 18.84 m
$l = \sqrt{4^{2} + 3^{2}} m = 5 m$
CSA = $π r l$ = 3.14 x 4 x 3 $c m^{2}$ = 37.68 $c m^{2}$
Now l x 2 = 37.68 $\Rightarrow$ l = 18.84 m