The length of minute hand of a clock is 7 cm .Find the distance covered by its outer end in 15 minutes

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Solution

Dear student,
$L e n g t h o f m i n u t e h a n d o f c l o c k i s 7 c m A n g l e d e s c r i b e d b y t h e m i n u t e h a n d i n 60 m i n u t e s = 360 ° A n g l e d e s c r i b e d b y t h e m i n u t e h a n d i n 1 m i n u t e s = \frac{360 °}{60 °} A n g l e d e s c r i b e d b y t h e m i n u t e h a n d i n 15 m i n u t e s = \frac{360 °}{60 °} \times 15 = 6 ° \times 15 = 90 ° D i s \tan c e c o v e r e d w i l l b e l e n g t h o f a r c c r e a t e d b y m i n u t e h a n d i n 15 m i n o r 90 ° D i s \tan c e = \frac{θ}{360} \times 2 πr = \frac{90}{360} \times 2 \times \frac{22}{7} \times 7 = \frac{1}{4} \times 2 \times 22 = 11 cm$
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