Question

The length of rectangle is $5cm$ more than its breadth. If the area of rectangle is $150sq.cm$. Find the sides of rectangle.

Answer 1

Let the shorter side of triangle $=x$ $cm$
The other side of the triangle $=(x+5)cm$
The area of reactangle
$(x+5)\left(x\right)=150$
$\Rightarrow$ $x^2+5x-150=0$
$\Rightarrow$ $(x+15)(x-10)=0$
$\Rightarrow$ either $x=-15$ or $x=+10$
Since the side cannot be negative
Therefore the value of $c=-15$ is negligible
When $x=10cm$, then the other side $=10+5=15cm$